Trinomials+Where+A=1

If you FOIL (x+2)(x+7), you get x 2 +9x+14, but where do those numbers come from? 9x is the sum of the two outer products, 7x and 2x. 14 is the product of the 7 and 2. To factor a standard quadractic trinomial (Ax 2 +Bx+C) using reverse FOIL when the A constant is equal to one, find two numbers that **add up** to B and **multiply to** C. These numbers will be the constant terms once the expression is factored. When C is greater than 0, the signs of the factored trinomial must be the same.
 * Reverse FOIL**

To factor x 2 -10x+24: Find 2 numbers that add to -10 and multiply to 24 -6 and -4 work, so put them into the factored solution
 * Example:**
 * (x-4)(x-6)**

If the C term is negative, the signs of the factorization will be different.
 * When C is Less Than 0**

x 2 -23x-24 Find 2 numbers that add to -23 and multiply to 24 1 and -24 work
 * Example**
 * (x+1)(x-24)**


 * A Helpful Tutorial Video:**
 * http://www.youtube.com/watch?v=kHxjfn7sG-g**